Question

A coil of 200 turns carries a current of
4 A. If the magnetic flux through the coil
is 6 x 10-5 Wb, find the magnetic energy
stored in the medium surrounding the
coil.​

Answer 1

Answer:

0.024 J (or joules).

Explanation:

Number of turns of the coil, $N=1$

Current, $I=4A$

Magnetic flux through the coil, N = 6 x $10^{-5}$ Wb

Energy stored in the coil, $U=\frac{1}{2} LI^{2}=\frac{1}{I^{2} }$

Self inductance of the coil, $L=\frac{N}{I}$ x Ф

$\\ U=\frac{1}{2} \frac{N}{I}$ Ф x $I^{2}$ = $\frac{1}{2} \frac{N}{I}$Ф = $\frac{1}{2}$ x 200 x 6 x $10^{-5}$ x 4

U = 2400 x $10^{-5}$

U = 0.024 J

Answer 2

Answer:

0.024 j or (joules) hope it goes well