Question

) A coil of 200 turns carries a current of 5mA and carries a magnetic flux of 2 x 10-8 WEBER.

The inductance is

(a) 0.2 MH (b) 2 MH (c) 0.02 MH (d) 0.1 MH​

Answer 1

Answer:

Explanation:

Given :

• Number of turns (N) = 200
• Current (I) = 5 mA
• Magnetic flux (ϕ) = 2 × 10^{-8} Weber

To Find :

• Inductance, L.

Formula to be used :

• Nϕ = L i

Where,

• N = number of turns
• ϕ = Magnetic flux
• L = Inductance
• i = Current

Solution :

★ Inductance,

Nϕ = L i (Formula)

⇒200 × 2 × 10^{-8} = L × 5

⇒ 400 × 10^{-8} = L × 5

⇒ L = 400 × 10^{-8}/5

⇒ L = 8 × 10^{-7} MH

Hence, Inductance is 8 × 10^{-7} MH.