Question

a coil of 200 turns has a cross sectional area of 900 mm2 . it carries a current of 2 ampere. the plane of the coil is perpendicular to a uniform magnetic field 0.5T. calculate
(1)the magnetic momentum of the coil and
(2) the torque acting on the coil. [0.36 Am2, 0.18Nm]

Answer 1

Answer:

Magnetic moment, M=NIA

                                                  =200 x 2 x 900 x 10⁻⁶

                                                   = 36 x 10⁻² Am²

Torque, τ = MBsinФ

                = 36 x 10⁻² x 0.5 x sin 90°

                = 18 x 10⁻² Am²T

Explanation:

Answer 2

Explanation:

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