a coil of 200 turns has a cross sectional area of 900 mm2 . it carries a current of 2 ampere. the plane of the coil is perpendicular to a uniform magnetic field 0.5T. calculate
(1)the magnetic momentum of the coil and
(2) the torque acting on the coil. [0.36 Am2, 0.18Nm]
Answers
Answered by
0
Answer: Magnetic moment, M=NIA
=200 x 2 x 900 x 10⁻⁶
= 36 x 10⁻² Am²
Explanation:
Similar questions