Question

A coil of 200 turns of wire is wound on a magnetic circuit of reluctance 2000.If a current of a 1A flowing in the coil is reversed in 10ms.Find the average e.m.f. induced in a coil.​

Answer 1

Explanation:

Given : No. of turns N = 200

Current flowing through coil I = 0.4 A

Magnetic flux linked with coil `Phi`

`=4mWb=4xx10^(-3)Wb`

To find :

Inductance of the coil L = ?

`NPhi=LI`

Solution :

`thereforeL=(NPhi)/(I)=(200xx4xx10^(-3))/(0.4)`

`=(800xx10^(-3))/(0.4)=2H`

L = 2 H