A coil of 50 turns is wound on an ivory frame 3 cm x 6 cm which rotates in a inagnetic filed B = 2 webm what will be the torque acting on it, if a current of 5 amperes passes through it and the plane of the coil makes an angle of 45°C with of the wings of the aero plane. the field.
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Answer: 9/10(√2)
Explanation:
torque is the vector cross product of external magnetic field and magnetic moment of coil , formula for magnetic moment is NiA, N is no of turns , A is area and i is current through coil.
T= 50 x 5 x 3/100 x 6/100 [2] x sin[45]
= 9/10√2
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