A coil of area 500 cm² and 2000 turn
is kept normal to a magnetic
field of 4× 10÷100000 wb 1/m². It is rotated through 180⁰ in 0.1s.
1- Calculate the averaged induced emf.
2- If the total resistance of the circuit be 20ohm calculate the
induced charge.
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Answer:
Given, A = 500 cm² = 500 × 10⁻⁴ = 0.05 m²
Number of turns = N = 1000
Magnetic field = B = 0.4G =0.4 × 10⁻⁴T
∆t = time taken = 1/10 = 0.1 sec
Coil turned θ = 0° to θ = 180° as shown in figure.
Change in flux =
so, change in flux = ΔΦ = -2NBA
We know,
Where Eav is average induced emf
So, Eav = 2NBA/∆t
=2 × 1000 × 0.4 × 10⁻⁴ × 0.05/0.1
=0.04 V
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