Question

A coil of area 80 cm square and 50 turns is rotating with 2000 evolution per minute about an axis perpendicular to a magnetic field of 0.05 tesla the maximum value of the emf developed is

Answer 1

e=NBAω; ω=2πf=2π×200060            ∴ e=50×0.05×80×10−4×2π×200060=4π3

Answer 2

The maximum value of the emf developed is 4.18 volts.

Explanation:

Given that,

Area of the coil, $A=80\ cm^2$

Number of turns, N = 50

Angular speed of rotation, $\omega=2000\ rev/min=209.43\ rad/s$

Magnetic field, B = 0.05 T

The induced EMF is given by :

$\epsilon=NAB\omega$

$\epsilon=50\times 80\times 10^{-4}\times 0.05\times 209.43$

$\epsilon=4.18\ V$

So, the maximum value of the emf developed is 4.18 volts. Hence, this is the required solution.

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Topic : Induced EMF

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