A coil of copper having 1000 turn is place in a magnetic field of B= 4T perpendicular to it axis.The cross sectional area of the coil is 0.05m².If it turn through 180° in 0.01 sec then find the emf induced in the coil
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Answer:0.4 V
Explanation:
Flux passing through the coil, =1000×4×10
−5
×0.05=2×10
−3
weber
Change in flux when the coil turns by 180
o
.
=2×10
−3
−(−2×10
−3
)
Δϕ=4×10
−3
e.m.f.=
dt
dϕ
=
0.01
4×10
−3
=0.4V
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