A coil of face area=25 cm^2 is facing normally a magnetic field of magnetic flux = 0.004 (wb)
Find the magnetic flux density, B
Answers
Answered by
1
Answer:
Flux density is simply the total flux divided by the cross sectional area of the part through which it flows - B = Φ / Ae teslas.
Answered by
1
Answer:
ANSWER A
The magnetic flux ϕ=B×A depends on the magnetic field, the area of the loop, and their relative orientation.
In this case, the magnetic field of flux density 1.0Wbm
−2
acts normal to a 80 turns coil of 0.01m
2
area.
Therefore, the Magnetic flux in 80 turns of coil = 0.01 * 80 = 0.8 T.
The time derivative of the flux is given as, dϕ/dt.
Therefore, the e.m.f induced in it, if this coil is removed from the field in 0.1 second is dϕ/dt = 0.8/0.1 = 8 V.
The e.m.f induced is 8V.
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