Question

A coil of L
=
5
x
10
−
3
H
and R
=
18
Ω
is abruptly supplied a potential of 5
volts .What will be the rate of change of current in 0.001
second? (
e
−
3.6
−
0.0273
)

Answer 1

emf is generated by a source. where as voltage is just the potential difference between two points in a circuit.

AS we know that

emf=LΔi/Δt

So just put values inductance and the rate of current in above equation .

emf=5(2)

emf=10V

Answer 2

Change in current will be 1 A

Explanation:

We have given inductance $L=10^{-3}H$

Emf e = 5 volts

Change in time is given by $\Delta t=0.001sec$

We know that emf is given by

$e=L\frac{di}{dt}$

$5=5\times 10^{-3}\frac{di}{0.001}$

$di=1A$

So change in current will be 1 A

Learn more

What rate of change of current in a 9.7 mH

solenoid will produce a self-induced emf of

35mV?

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