Question

A coil of n turns a area is placed in uniform transverse magnetic field B if turn through 180 about it’s one diameter in 2sec find rate of change of magnetic flux through coil

Answer 1

The rate of change of magnetic flux through coil is e = - 10×nBA

Explanation:

(2) emf, e = − ndφ / dt

e = −n(ϕ1−ϕ2) / t

e = −n BA (cos 0°− cos 180°)  / 0.2

e = −nBA (1+1) / 0.2

e = −2 × nBA / 0.2

e = - 10×nBA

Negative sign shows the direction of emf.

Hence the rate of change of magnetic flux through coil is e = - 10×nBA

Also learn more

The magnetic flux through a coil perpendicular to the plane is varying according the relation phi = (5t^3 + 4t^2 + 2t - 4) Wb. Calculate the induced current through the coil at t = 2 seconds,if the resistance of the coil is 5 ohms ?

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Answer 2

Answer:

-NBA

Explanation:

Flux through a coil on 'N' turns is given by the formula

flux = N(B.A)

      = N(BA cos x)

(Where x is the angle between area vector and direction of field)

Here: x= 180

         hence rate of change of flux = NBA cos 180 = -NBA