A coil of one loop is made by a wire of length L
and there after a coil of two loops is made by same
wire. The ratio of magnetic field at the centre of
coils respectively :-
(1) 1:4
(2) 1:1
(3) 1: 8
(4) 4:1
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Answer:
Explanation:
Given : Length of the wire is L
Let radius of first and second loop be R
1
and R
2
respectively.
According to the question L=2πR (first loop) ..............(1)
Also L=2×2πR
2
(second loop) .............(2)
From (1) and (2), 2πR
1
=2(2πR
2
) ⟹
R
1
R
2
=
2
1
Magnetic field at the center of the coil of radius R is given by B=
2R
μ
o
nI
⟹
B
2
B
1
=
n
2
R
1
n
1
R
2
=
2
1
×
2
1
=
4
1
(∵n
2
=2, n
1
=1)
Thus B
1
:B
2
=1:4
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