Question

A coil of radius 1 cm and of turns 100 is placed in
the middle of a long solenoid of radius 5 cm. and
having 5 turns/cm. parallel to the axis of solenoid
The mutual inductance in millihenery will be
(1) 0.0316 (2) 0.063 (3) 0.105 (4) Zero​

Answer 1

Explanation:

ANSWER

Field inside solenoid = B=μNi

N - number of turns per length in solenoid =800/m

Flux linking the smaller coil = λ=100×πr

2

B=100×πr

2

μNi

mutual inductance = M=

i

λ

=100×πr

2

μN=3.15mH