Question

A coil of resistance 100 ohm and inductive reactance 200 ohm is connected across a supply voltage of 230v. find the supply current ​

Answer 1

A coil of resistance 100 ohm and inductive reactance 200 ohm are connected connected across a supply voltage 230 volt.

To find : the supply current.

solution : resistance of coil , R = 100 Ω

inductive resistance, $X_L$= 200 Ω

impedance, $X=\sqrt{R^2+X_L^2}$

⇒X = √{100² + 200²} = 100√5 Ω = 223.6 Ω

now supply current = voltage/impedance

= 230/223.6

= 1.0286 A

Therefore the supply current is 1.0286 A.

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Answer 2

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Given,

• Coil of resistance = 100ohm
• Indictive reactance = 200ohm
• Voltage = 230V

To Find:-

⭐Supply of current⭐

Formula used:-

$x = \sqrt{ {r}^{2} + x_{l} {}^{2} }$

Current supply = voltage /impedance.

Calculations:-

$x = \sqrt{ {r}^{2} + { x_{l} }^{2} }$

Now,substituting the given values,

= √{100² + 200²}

= 100√5 Ω

Impedance = 223.6 Ω

Now,

Current supply = Voltage /Impedance

=230/223.6

=1.0286A.

so,

The supply of current is 1.0286A.