Question

a coil of turns 100 carries a current of 5mA and create a magnetic flux of 10*-5 .what is it induction​

Answer 1

Answer:

Inductance of the coil is 20x10⁻² H or 0.2 H.

Explanation:

N = 100 , I = 5 mA,   Φ = 10⁻⁵ weber

Nφ = L I By putting the all values

100 × 10⁻⁵ = L × 5 × 10⁻³⇒L = 100 × 10⁻⁵/  5 × 10⁻³ = 20x10⁻⁵x 10³ =20x10⁻² H

Answer 2

The answer for the inductance is 0.2mH.

Given,

Number of turns in the coil = 100

Current = 5mA

Magnetic flux = $10^{-5}$

To Find,

Inductance = ?

Solution,

To calculate the inductance, the formula is given as follows,

L = NФ/i

where, L = inductance

N= no. of turns of coil

Ф= magnetic flux of current

i= current

Substituting the given values in the formula,

No. of turns in the coil N = 100

Magnetic flux Ф = $10^{-5}$

Current i = 5 mA

L = NФ/i

= 1OO x $10^{-5}$/ 5

= $10^{-3}$/ 5

= 0.2 x $10^{-3}$

= 0.2 mH

Therefore the inductance is 0.2mH.

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