Question

A coil of wire enclosing an area 100cm² is placed with its plane making an angle 60° with the magnetic field of strength 10-T.What is the flux through the coil?​

Answer 1

Answer:

1. Flux through the coil, ϕ = BA cosθ = 10-1 x 100 x 10-4 x cos30º = 3√232 x 10-3 wb Here, ϕf = 0; dt = 10-3 s Induced emf, E = −dϕdt−dϕdt = −(ϕf−ϕi)Δt−(ϕf−ϕi)Δt ∴ E = −[0−3√2×10−3]10−3−[0−32×10−3]10−3 = 3√232 = 0.866v

Explanation:

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Answer 2

Answer:

Flux through the coil, ϕ = BA cosθ

= 10-1 x 100 x 10-4 x cos30º

= 3√232 x 10-3 wb

Here, ϕf = 0; dt = 10-3 s

Induced emf, E = −dϕdt−dϕdt = −(ϕf−ϕi)Δt−(ϕf−ϕi)Δt

∴ E = −[0−3√2×10−3]10−3−[0−32×10−3]10−3

= 3√232 = 0.866 v

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