Question

A coil of wire of a certain radius has 600 turns .......the self inductance of a second similar coil of 500 turns will be?
pls solve this question given in picture.thankyou​

Answer 1

Answer:

(b) 75 mH

Explanation:

self Inductance : L ~ N^2

hence L2/L1 = (N2/N1)^2

then....L2 = [(N2/N1)^2] × L1

L2 = [(500/600)^2] × 108

L2 = 75 mH

Note :

directly proportional symbol used as : ~