Science, asked by simransagar, 1 year ago

A coil or N turns of insulated copper wire is closely wound over a cardboard pipe. The free ends of the coil wire are connected to a battery, a rheostat and an open key as shown. A is a point on the axis of the coil. Answer the following questions with reason:
(1) Which direction will a magnetic needle stay when placed at A.
(2) What will happen when key K is closed?
(3) Keeping K closed when moving contact C of the rheostat is moved from X to Y' what will happen.
(4) If a pivoted needle of iron were placed at A, how will the answers to (1) and (2) change.

Answers

Answered by riyabhati12
22
Solution:

(i) When current is made to pass through coil B, by plugging the key in, for that instant, the galvanometer connected to coil A shows a deflection, i.e., current passes through coil A as well.

(ii) When current is stopped through coil B by taking the plug of the key out, for that instant, the galvanometer connected to coil A again shows a deflection, this time, however, in the opposite direction. That is, a current passes through coil A in the opposite direction.

The observations are made because whenever we change the current in the coil B, the magnetic field associated with it and the coil A in its proximity changes. At the very instant of plugging the key in or taking the plug out, there is an instantaneous flow of current and a change in the magnetic field associated with the coil B. During this instantaneous moment, the current in coil B reaches from zero to the maximum or from the maximum to zero. This changing magnetic field of coil B induces a current in the coil A.

The phenomenon is known as electromagnetic induction.

kovadiyamanjur: thanks
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