Question

A coil with 150 turn, 5.0 cm radius, and a resistance of 12 Ω surrounds a solenoid with 230 turns/cm
and a radius of 4.5 cm. The current in the solenoid changes at a constant rate from 0 to 2.0 A in 0.10
s. Find the magnitude of the induced current in the 150-turn coil. (10 points)

Answer 1

ɛ = 150 × d/dt(μ0ni) × p × (4.5100)^2

= 150 × 4π × 10^−7× 230 × 10^2/100×2/0.1 × π × 4.5 × 4.5/10^4

i = ɛ/12 = 600π^2 × 460 × 10^3 × 10^−7/12 × (4.5)^2/10^4

= 0.04657500 × 10^−6

≈ 5A