Question

A coilof resistance 10 ohm and 1000 turns have the magnetic field of 5.5×10^-4 if the magnetic flux vhanged to 5×10^-4 in 0.1 sec then the induced charge in coil is

Answer 1

Hey mate,

◆ Answer-

Q = -5×10^-3 C

◆ Explaination-

# Given-

R = 10 ohm

N = 1000 turns

Φ1 = 5.5×10^-4 T

Φ2 = 5×10^-4 T

# Solution-

Charge induced in coil is given by-

Q = N (Φ2-Φ1) / R

Q = N (5×10^-4 - 5.5×10^-4) / 10

Q = -1000 × 0.5×10^-4 / 10

Q = -5×10^-3 C

Charge induced in the coil is -5×10^-3 C.

Hope this helps you...