A coin are tossed simultaneously 500 times , and we get two head 105 times and one head 275
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Two coins are tossed 600 times.
Therefore, n(S)=600.
Let A be the event of getting two heads, n(A)=138.
Let B be the event of getting one head, n(B)=192.
Let C be the event of getting no heads, n(C)=270.
We have to find the probability of getting no tails.
The Probability of getting no tails is the same as the probability of getting two heads.
Therefore, the probability of getting no tails is
600
138
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