A coin had toss 3 times find the probality of getting atleast one tail
Answers
Answered by
2
Answer:
7/8
Step-by-step explanation:
P(at least one tail)
= 1 - P(no tails)
= 1 - P(3 heads)
= 1 - (1/2)×(1/2)×(1/2)
= 1 - 1/8
= 7/8
Answered by
0
Answer:
7/8
Step-by-step explanation:
This way is only good for small sample space. Gravy's way is better for more general understanding I think.
Sample space = { HHH, HHT, HTH, HTT, THH, THT, TTH, TTT } ... 8 outcomes
Event = { HHT, HTH, HTT, THH, THT, TTH, TTT } ... 7 outcomes
Probability = 7/8
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