A coin is biased so that it has a 60% chance of landing on heads. If it is thrown three times, find the probability of getting: a) Three heads b) 2 heads and a tail c) At least one head
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2
Answer:
Given a biased coin such that heads is 3 times as likely as tails. The coin is tossed twice.
P(H)=
4
3
and P(T)=
4
1
Let T be the random variable for the number of tails.
P(T=0)=P(HH)=
4
3
×
4
3
=
16
9
P(T=1)=P(HT,TH)=
4
3
×
4
1
+
4
3
×
4
1
=
16
3
+
16
3
=
8
3
=
16
6
P(T=2)=P(TT)=
4
1
×
4
1
=
16
1
Hence (B) is the correct answer.
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