A coin is dropped from a height of 80 m. How fast will it fall, just before it hits the ground? [Take g = 10 m/s²,Hint: For a falling body, the total PE at the greatest height will be equal to the KE.,just before it touches the ground]
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Answer:
Explanation:
v=√2gh0
v=√2×10×80
v=√1600
v=40m/
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