Physics, asked by rajayush537, 1 year ago

A coin is dropped from a tower.it moves through a distance of 24.5 in the last second before hitting the ground find the height of the tower

Answers

Answered by JunaidMirza
56
Distances travelled in last second
S = u + a(n - 1/2)
24.5 = 0 + 9.8(n - 1/2)
n = 24.5/9.8 + 0.5
n = 3rd second

Total time of flight is 3 seconds

Height of the tower
H = 0.5gt^2
= 0.5 × 10 × 3^2
= 45 m

Height of the tower is 45 m

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Answered by aravinds6
2

Answer:

Distances travelled in last second

S = u + a(n - 1/2)

24.5 = 0 + 9.8(n - 1/2)

n = 24.5/9.8 + 0.5

n = 3rd second

Total time of flight is 3 seconds

Height of the tower

H = 0.5gt^2

= 0.5 × 10 × 3^2

= 45 m

Height of the tower is 45 m

Explanation:

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