A coin is dropped from a tower.it moves through a distance of 24.5 in the last second before hitting the ground find the height of the tower
Answers
Answered by
56
Distances travelled in last second
S = u + a(n - 1/2)
24.5 = 0 + 9.8(n - 1/2)
n = 24.5/9.8 + 0.5
n = 3rd second
Total time of flight is 3 seconds
Height of the tower
H = 0.5gt^2
= 0.5 × 10 × 3^2
= 45 m
Height of the tower is 45 m
S = u + a(n - 1/2)
24.5 = 0 + 9.8(n - 1/2)
n = 24.5/9.8 + 0.5
n = 3rd second
Total time of flight is 3 seconds
Height of the tower
H = 0.5gt^2
= 0.5 × 10 × 3^2
= 45 m
Height of the tower is 45 m
rishilaugh:
thanks
Answered by
2
Answer:
Distances travelled in last second
S = u + a(n - 1/2)
24.5 = 0 + 9.8(n - 1/2)
n = 24.5/9.8 + 0.5
n = 3rd second
Total time of flight is 3 seconds
Height of the tower
H = 0.5gt^2
= 0.5 × 10 × 3^2
= 45 m
Height of the tower is 45 m
Explanation:
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