Question

A coin is dropped from a tower. It moves through a distance of 24.5 meter in the last second before hitting the ground. Find the height of the tower.
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Answer 1

Let the total height of the tower is h and the total time is taken to reach the ground is t.

The height is given as,

h= ½gt² (1)

The height before last seconds is given as,

h−24.5=½

g(t−1)²½gt²−24.5=½g(t)²+½g−gt

t=3s

Substitute the value of t in the equation (1), we get

h½×9.8(3)²h=44.1m

Thus, the height of the tower is 44.1m.