a coin is dropped in a beaker containing mercury settles down at the bottom after 3 seconds. if the depth of mercury in the beaker is 1.5 feet. calculate the pressure on the country at that point
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RI=
apparent depth
real depth
Substituting,
3
4
=
apparentdepth
12
Therefore, apparent depth=
4
12×3
=9
The height by which it appears to be raised is 12−9=3cm
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a coin is dropped in a beaker containing Mercury settles down at the bottom after 3 seconds if the depth of the mercury in a beaker is 1.5 calculate the pressure on the coin at that point
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