A coin is placed at a depth of 3 m in a beaker containing water. The refractive index of water is 1.33. What is the apparent depth of the coin?
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Answer:
RI=
apparent depth
real depth
Substituting,
3
4
=
apparentdepth
12
Therefore, apparent depth=
4
12×3
=9
The height by which it appears to be raised is 12−9=3cm
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