Question

A coin is placed at a depth of 3 m in a beaker containing water. The refractive index of water is 1.33. What is the apparent depth of the coin?

Answer 1

Answer:

RI=

apparent depth

real depth

Substituting,

3

4

=

apparentdepth

12

Therefore, apparent depth=

4

12×3

=9

The height by which it appears to be raised is 12−9=3cm