Question

A coin is placed at the bottom of a beaker containing
water (refractive index = 4/3) to a depth of 12 cm.
By what height the coin appears to be raised when
seen from vertically above ?
Ans. 3 cm





Why the hell my ans is coming 9?????

Answer 1

Answer:

According to me it will be

4/3=12/x

x=12×3/4

x=36/4

x= 9 ...

Now the answer of this question will be 9 cm.

Answer 2

Answer:

the answer is 3 cm

Step-by-step explanation:

hope it helps u

tq