Question

A coin is placed at the bottom of a beaker containing water (n = 4/3) up toa height of 0.06m. when viewed fromthe top it appears nearer by1) 0.01 m3) 0.02 m2) 0.015 m4) 0.025 m​

Answer 1

Answer:

Option 2) 0.02m

Explanation:

Refractive index of water= 4/3

true height= 0.06m

apparent height= ?

Apparent height = H(refractive index of water/refractive index of air)

Apparent height = 0.06(4/3/1)

Apparent height = 0.06×1.33

Apparent height = 0.08

Therefore it is nearer by apparent height - true height

Difference = 0.08-0.06

It appears nearer by 0.02m