a coin is placed at the bottom of a swimming pool.To obtain a vertical shift of 20 cm of the image of the coin,the required hieght of the water column is?
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Answer:
Explanation:
Let here the actual depth is d and the apparent depth is d1 .
So the vertical shift is d - d1 = 20 cm.
Now the refractive index is , μ=d/d1
⇒d1=d/μ
So ,d−d1=d−d/μ
=d(μ−1/)μ
20=[d×(4/3−1)] / (4/3)
=d×1/4
d=80 cm .
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Answer:
e cough up for a while now but I can't
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