Question

A coin is placed in a tumbles, water is then filled in the tumbler to a height of 20cm. If the refractive index of water is 4/3, calculate the apparent depth of the coin.

Answer 1

Answer:

Virtual Depth of the coin is 15−3.75=11.25cm

Refractive index =

virtual depth

real depth

=15/11.25=1.33

Answer 2

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Given,

Real depth = h = 20cm

Refractive index = n = $\frac{4}{3}$

We know,

n = $\frac{Real \:depth}{Apparent \:depth}$

$\frac{4}{3}$ = $\frac{20}{Apparent \:depth}$

Therefore, Apparent depth = 15cm