Question

A coin is placed inside beaker, containing water to a height of 2 m. What is the apparent depth of the coin from the surface of water? (R.I. of water )

Answer 1

$\huge{\underline{\tt{\blue{Answer-}}}}$

$RI= \dfrac{ real \ depth} {apparent \ depth}$

$1.33= \dfrac{2}{apparent \ depth}$

$apparent \ depth = 1.503 m$

The height by which it appears to be raised is 2-1.503= 0.49m

Answer 2

Real depth by appearnt depth