a coin is placed on a rotating disc than what will be the change in its angular speed
justify.
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Answer:
When the coin is just on the verge of slipping, it just overcomes the force of static friction (F
s
) . which acts as centripetal force for being that coin in the circular motion.
So we have
F
s
=mω
2
r
If we double the ω, then r will also self adjust to a new r
′
, since the static friction will remain same. We have
mω
2
r=m(2ω)
2
r
′
⇒r
′
=
4
r
cm=
4
4
cm=1 cm
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