A coin is placed on a rotating turning table slips if placed at minimum dist of 9cm from centre if angular velocity of turn table is tripled
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Answer:
Explanation:
(w= angular velocity)
F= m w^2 r
F slip= m w^2 40. --> eqn(1)
F slip= m (2w)^2 R2
F slip=4m w^2 R2 --> eqn(2)
solving 1 and 2
m w^2 40 = 4 m w^2 R2
so R2 = 10 cm
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