Math, asked by Taybaa3719, 1 year ago

A coin is released inside a lift at a height of 2 m from the floor of the lift. the height of the lift is


10 m. the lift is moving with an acceleration of 11 m/s downwards. the time after which the coin wi


strike with the lift is

Answers

Answered by Anonymous
1
distance to be covered=2m
accelaration =(10-11)m/s^2=-1m/s^2
s=ut+1/2at^2
2=0+1/2(-1)t^2
2=-1/2t^2
the coin will never strike if acceleration is 11m/s^2
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