Physics, asked by riya558, 1 year ago

A coin is rolling in a plane surface .what fraction of its total kinetic energy is rotational

Answers

Answered by AnnSandra
41
In case of rolling without slipping the angular velocity (ω) and the velocity of centre of mass (v) are related as: v = Rω.

Moment of inertia of the coin (disc), I = 1/2mr​2

Total kinetic energy, K = Translational kinetic energy + Rotational kinetic energy

 

or, K = 1/2 mv2​ + 1/2 Iω2

 

We can write rotational kinetic energy as: 

 

1/2 Iω​2 = (1/2 )×(1/2 mr2​) (ω​2) = 1/4 m (rω)2 = 1/4 mv​2 

 

Thus,

 

K total = Kt + Kr 

 

2Kr = Kt

 

Ktotal = 3 Kr

 

Fraction of rotational kinetic energy

 

Kr/3 Kr = 1/3


riya558: thanks ann
Answered by sahalhasvad123
0

Explanation:

KE rotational=1/4mv^2

total KE= 3/4mv^2

fraction of total kE is rotational

KE rotational ÷total KE = 1/3

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