Question

A coin is so unbalanced that you are likely to get two heads in two successive throws as you are to get tail in one. What is the probability of getting heads in a single throw?

Answer 1

Answer:

Probability of getting heads in single throw is 2/1

Answer 2

0.618 is the probability of getting heads in a single throw

Step-by-step explanation:

Let say probability of getting head in a single throw = x

then probability of getting tail in 1 single throw = 1 - x

probability of getting two heads in two successive throws = x × x

$= {x}^{2}$

${x}^{2} = 1 - x \\ {x}^{2} + x - 1 = 0$

$x = \frac{ - 1 + \sqrt{ {1}^{2} - 4(1)( - 1)}}{2}$

probability can not be -ve hence only +ve value considered

$x = \frac{ \sqrt{5} - 1}{2}$

x= 0.618

0.618 is the probability of getting heads in a single throw

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