Question

a coin is thrown 3 times. what is the probability that at least one head is obtained a. 0.5 b. 1/8 c.7/8 d.2/10

Answer 1

p e   =   favorable /  total outcomes

a is answer  

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Answer 2

The probability that at least one head is obtained is $\frac{7}{8}$

Solution:

When a coin is tossed 3 times, sample space is:

(HHH, HHT, HTH THH,TTT,TTH,THT,HTT)

Thus,

Total number of possible outcomes = 8

favorable outcomes = at least 1 head =  1 head or 2 head or 3 head

favorable outcomes = HHH, HHT, HTH THH,TTH,THT,HTT

Thus,

Number of favorable outcomes = 7

$Probability = \frac{ \text{ Number of favorable outcomes }}{ \text{ Total number of possible outcomes }} \\\\Probability = \frac{ 7 }{8}$

Thus, the probability that at least one head is obtained is $\frac{7}{8}$

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