Question

A coin is tossed 10 times and outcomes are observed as H, T, H, H, T, H,
T, H, H, T. Calculate the percentage chance of occurrence of
Head (H) and Tail (T)

please give the full solution​

Answer 1

Step-by-step explanation:

Percentage chance of Heads = 60%

Percentage chance of Tails = 40%

Step-by-step explanation:

The sample space of the outcomes for the 10 tosses of a coin is:

S = {H, T, H, H, T, H, T, H, H, T}

Number of Heads = n (H) = 6.

Number of Tails = n (T) = 4.

Compute the probability of Heads:

\begin{gathered}\neq P(Heads)=\frac{Number\ of\ Heads}{Total\ number\ of\ outcomes}\\ =\frac{6}{10}\\ =0.60\ or\ 60\%\end{gathered}



=P(Heads)=

Total number of outcomes

Number of Heads

=

10

6

=0.60 or 60%

Compute the probability of Tails:

\begin{gathered}P(Tails)=\frac{Number\ of\ Tails}{Total\ number\ of\ outcomes}\\ =\frac{4}{10}\\ =0.40\ or\ 40\%\end{gathered}

P(Tails)=

Total number of outcomes

Number of Tails

=

10

4

=0.40 or 40%

Thus, the percentage chance of occurrence of Head (H) and Tail (T) are 60% and 40% respectively.

hope it will help you