Question

A coin is tossed 10 times. What is the probability of getting 4 tails and 6 heads?​

Answer 1

Answer:

With fair coins and fair tossing, the number of ways to get 6H+4T = 10!/(4!)(6!).

The total number of possible outcomes = 2^10.

Therefore the probability as requested = [10!/(4!)(6!)]/(2^10) = 210/1,024 = 105/512 = .205078125 ~ 20.5%