Question

A coin is tossed 1000 time with following frequencies: head: 455; tail:545.find the probability of tail

Answer 1

Probability is total number of event/total number of toss. Show tails is P(E)=545/1000 =109/200

Answer 2

Total number of tosses = 1000

No of head = 455

No of tail = 545

Now,

P (getting a tail) = $\mathsf {\frac{number \: of \: tails}{total \: no \: of \: tosses} }$

P ( getting a tail) = $\mathsf {\frac{545}{1000} }$

P (getting a tail) = 0.545