Question

a coin is tossed 1000 times with the following frequencies:
Head: 455, Tail : 545
compute the probability for each event.​

Answer 1

Answer:

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Step-by-step explanation:

Total number of outcomes = 1000

FAVOURABLE CASES = 455

Probability (H) = FAVOURABLE CASES / TOTAL OUTCOMES

= 455/1000

= 0.455

Therefore, the probability of event head is 0.455.

now probability of event tail ;

favourable cases = 545

total cases = 1000

= 545/1000

= 0.545

Therefore, the probability of event tail is 0.545.

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Answer 2

Step-by-step explanation:

Given:  A coin is tossed 1000 times with the following frequencies:

Head: 455, Tail: 545

Total number of trials = 1000.

Let us denote the events of getting head and event of getting tail be E and F .

Number of trials in which the event E happens = 455

So, Probability ( E) = (Number of trials in which the event E happens) / (Total number of trials)

P(E) = 455/1000  

P(E) = 0.455

Probability of the event getting a tail, P(E) =  0.455

and,

Number of trials in which the event  F happens = 545

Probability of the event getting a tail, P(F) = 545/1000 = 0.545