A coin is tossed 2 times what is the probability of getting one head atmost one head
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Ok..given , a coin is tossed 2 times . therefore . sample space =
{HH HT TH TT}
now first u need to understand the meaning of atmost.
At most one head : 1 head is ok and none head is also ok , but more than 1 head are not applicable.
therefore probability of getting atmost 1 head = 3/4 [HT TH TT}
{HH HT TH TT}
now first u need to understand the meaning of atmost.
At most one head : 1 head is ok and none head is also ok , but more than 1 head are not applicable.
therefore probability of getting atmost 1 head = 3/4 [HT TH TT}
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total outcomes,n= (T,T),(H,H),(T,H),(H,T)=4
favourable cases for getting one head,m1=(T,H),(H,T)=2
probability of getting one head,P(E1)
=m1/n
=2/4
=1/2
favourable cases for getting atmost one head,m2=(T,T),(H,T),(T,H)=3
probability of getting atmost one head,P(E2)=m2/n
=3/4
favourable cases for getting one head,m1=(T,H),(H,T)=2
probability of getting one head,P(E1)
=m1/n
=2/4
=1/2
favourable cases for getting atmost one head,m2=(T,T),(H,T),(T,H)=3
probability of getting atmost one head,P(E2)=m2/n
=3/4
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