a coin is tossed 200 times and is found that a tail comes up for 120 times find the probability of getting a tail
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12
coin is tossed 200 times therefore we will have 200 results
.let 'S' be the sample space
.:n(S)=200
let 'A' be the number of times we get a tail
.:n(A)=120
.:P(A)=n(A)/n(S)
=120/200
=12/20
=6/10 = 60%
.:P(A)=60%
ANSWER
Possibility of getting a tail is 60%
.let 'S' be the sample space
.:n(S)=200
let 'A' be the number of times we get a tail
.:n(A)=120
.:P(A)=n(A)/n(S)
=120/200
=12/20
=6/10 = 60%
.:P(A)=60%
ANSWER
Possibility of getting a tail is 60%
Answered by
11
COIN TOSSED = 200 TIMES
TALES COME = 120
SO THE PROBABILITY OF TAIL IS =
THE NUMBER OF OUTCOMES TAIL /TOTAL NUMBER OF TRIALS
120/200 DIVIDE IT
= 0.6
TALES COME = 120
SO THE PROBABILITY OF TAIL IS =
THE NUMBER OF OUTCOMES TAIL /TOTAL NUMBER OF TRIALS
120/200 DIVIDE IT
= 0.6
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