Math, asked by Griezmann6623, 9 months ago

A coin is tossed 3 times. events a and b are, a: no head appears b:no tail appears. show that a and b are mutually exclusive​

Answers

Answered by myrakincsem
5

Step-by-step explanation:

The coin is tossed three times. The possible outcomes are

S= {HHH, HHT, HTH, TTH, THT, TTT, THH, HTT}

Now the event A which say that no head appears can be written as

A={TTT}

Event B which says that no tail appears is written as

B={HHH}

Now to prove that they are mutually exclusive

A ∩ B= {TTT} ∩ {HHH}

As we can see that

A ∩ B =∅

Hence, proved they are mutually exclusive

Answered by maheshwarinatraj4121
0

Answer:

HOPE THE ABOVE GIVEN ATTACHMENT WILL HELP YOU......

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