Question

A coin is tossed 3 times the probability of getting head and tail alternatively is

Answer 1

There are two outcomes that satisfy the alternate condition HTH and THT. Head and tail come alternatively in these two outcomes,
Total possibilities=8
Number of requirea outcome=2
Probability=2/8=1/4
So number 3) is correct answer

Answer 2

Answer:

Probability of getting Head & Tail alternatively is   $\frac{1}{4}$

Step-by-step explanation:

Given: A coin is tossed 3 times.

To find: Probability of getting head and tails alternatively.

A coin is tossed 3 times

⇒ Total no of Outcomes = 2³ = 8

Sample Space or All Outcomes = { (H,H,H) , (H,H,T) , (H,T,H) , (H,T,T) , (T,H,H) , (T,H,T) , (T,T,H) , (T,T,T) }

Here H for head & T for Tail.

Thus, Favorable outcomes are = { (H,T,H) , (T,H,T) }

$Probability=\frac{No.\,of\,Favorable\,outcome}{Total\,No.\,of\,outcomes}$

$Probability=\frac{2}{8}=\frac{1}{4}$

Therefore, Probability of getting Head & Tail alternatively is   $\frac{1}{4}$