a coin is tossed 3 times write the event a of getting at least 2 heads and even be for of getting no Head Right event A and B also write the number of simple points
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p(event A)=3/6=1/2
p(event B)=1/6.
p(event B)=1/6.
Smitwaikar1111:
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3 coins are tossed so,
total no. of elementary event = 8
(i) conditions of getting at least two Heads are
{HHH, HHT, HTH, THH}
hence Total no. of favorable events is 4
so P(Event A) = 4/8 = 1/2
(ii) condition of getting no head is {TTT}
so, P(event B) = 1/8
MARK AS BRAINLIEST IF IT WAS USEFUL TO YOU..
total no. of elementary event = 8
(i) conditions of getting at least two Heads are
{HHH, HHT, HTH, THH}
hence Total no. of favorable events is 4
so P(Event A) = 4/8 = 1/2
(ii) condition of getting no head is {TTT}
so, P(event B) = 1/8
MARK AS BRAINLIEST IF IT WAS USEFUL TO YOU..
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