Question

A coin is tossed 3times find probability atleast 2heads

Answer 1

the required probability is 2/3

Answer 2

Answer:

$\frac{1}{3}$

Step-by-step explanation:

Given,

            total number of possible outcomes = 6

         total numbers of favorable outcomes = 2

Now,

       Probability = $\frac{total number of possible outcomes}{total numbers of favorable outcomes}$

                         = $\frac{2}{6}$

                         = $\frac{1}{3}$

Therefore, the probability of getting  2 at least heads is  $\frac{1}{3}$